3q^2-118.5q-328.5=0

Solution for 3q^2-118.5q-328.5=0 equation:

3q^2-118.5q-328.5=0

a = 3; b = -118.5; c = -328.5;
Δ = b2-4ac
Δ = -118.52-4·3·(-328.5)
Δ = 17984.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-118.5)-\sqrt{17984.25}}{2*3}=\frac{118.5-\sqrt{17984.25}}{6}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-118.5)+\sqrt{17984.25}}{2*3}=\frac{118.5+\sqrt{17984.25}}{6}
$